If a solution contains 3 equivalents of solute per liter, the normality is

If a solution contains 3 equivalents of solute per liter, the normality is

• A. 1 N
• B. 3 N
• C. 0.3 N
• D. 30 N

Answer: (B)

Normality equals the number of equivalents of solute per liter of solution. If the solution contains 3 equivalents per liter, the normality is 3 N. This directly reflects how many reactive units are present in each liter. Remember that normality can differ from molarity depending on the reaction context (the equivalence factor), but in this case the given 3 equivalents per liter converts straight to 3 normal.

Normality equals the number of equivalents of solute per liter of solution. If the solution contains 3 equivalents per liter, the normality is 3 N. This directly reflects how many reactive units are present in each liter. Remember that normality can differ from molarity depending on the reaction context (the equivalence factor), but in this case the given 3 equivalents per liter converts straight to 3 normal.